2x^2+x-21=(x-3)(2x+7)

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Solution for 2x^2+x-21=(x-3)(2x+7) equation: 



2x^2+x-21=(x-3)(2x+7)

We move all terms to the left:

2x^2+x-21-((x-3)(2x+7))=0

We multiply parentheses ..

2x^2-((+2x^2+7x-6x-21))+x-21=0



We calculate terms in parentheses: -((+2x^2+7x-6x-21)), so:

(+2x^2+7x-6x-21)

We get rid of parentheses

2x^2+7x-6x-21

We add all the numbers together, and all the variables

2x^2+x-21

Back to the equation:

-(2x^2+x-21)



We add all the numbers together, and all the variables

2x^2+x-(2x^2+x-21)-21=0

We get rid of parentheses

2x^2-2x^2+x-x+21-21=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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